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第12章 三相电路
一、选择题
如图12-1所示为对称三相电路,电源线电压U1=1OOV,线电流I1=2A,负载功率因数λ=cosφ=0.8(感性),功率表接法也如图所示,则此时功率表读数为( )。[上海交通大学2005研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image437.jpg?sign=1738881548-EfGJicZQ1NEl6n8GcI1waXp8L9RHFEKh-0-42ffa2b4651fa501c4ed930eec389595)
图12-1
A.208W
B.120W
C.173W
D.0
【答案】A
【解析】选为参考相量,
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image440.jpg?sign=1738881548-Lwa3JtyD12H8IqjZ3858mkKDFC9FblUj-0-c7f79c148178018954d6753b5ba0f058)
二、填空题
1.在如图12-2所示的对称三相正弦交流电路中,所有三只安培表的读数都是10A,如果外加三相对称线电压保持不变,而将AB相负载断开,则电流表A1的读数为_____,电流表A2的读数为_____,电流表A3的读数为_____。[浙江大学2004研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image441.jpg?sign=1738881548-MrFBSDQQ10mv3mA0bOuzWu1oKs0l7wyj-0-54c5a2ce5927119aee212c7d4186d247)
图12-2
【答案】5.77A; 5.77A; 10A
【解析】按一般正弦稳态电路分析方法即可得出结果。
2.图12-3所示三相对称电路中开关S合上时电流表A1的读数是A,则开关S合上时电流表A2的读数是( );A3的读数是( );开关S断开时电流表A1的读数是( );A2的读数是( );A3的读数是( )。[华南理工大学2010研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image443.jpg?sign=1738881548-0ZrqVqFOin04HIjqOABnOykoxyvLZxMF-0-93920d21de510d0dad544c8e764914f8)
图12-3
【答案】;
;
;10A;10A
【解析】根据三相电路的对称性,在开关闭合后,三表读数是相同的,即都是;在开关打开之后,
读数不变认为
,
和
的电流表读数变化,线电流变为相电流,为10A。
3.某三角形联接的电力负载,线电压、
及
严重不对称且含有5、7次谐波,该三相负载线电压的零序分量为( )。[华南理工大学2009研]
【答案】
【解析】将不对称的三相线电压分解为三组对称的相量,分别为正序分量、负序分量和零序分量。由于三相线电压中各相对应的正序分量相量和为0、负序分量相量和为0,并且各谐波分量只含有交流分量(即正序、零序分量),无零序分量。则三相线电压的相量和即为三倍的零序分量。即有:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image452.png?sign=1738881548-Nk9GNWhCddEQgpJMgBtodFPm8UmuYUa4-0-69124f4175a576bced4e3c74d7e0ac72)
4.如图12-4所示对称三相电路中,已知星形连接负载(复)阻抗Z=5+j8.66Ω,若已测得电路无功功率
图12-4
【答案】由Z=5+j8.66Ω可得阻抗角为
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image455.jpg?sign=1738881548-5AfsBtTR2ggYxiRKZRPswGNXAS3xwSJR-0-2d909b5b6dea4969a79bc9ce618f95f0)
于是有功功率为
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image456.jpg?sign=1738881548-YMD3OZBiKXadDseMqtXsYyEV2kz6dbSo-0-bf0df4ce1a7402604f7baa6974d17c05)
三、计算题
1.线电压为
的三相电源上接有两组对称三相负载:一组是三角形联结的电感性负载,每相阻抗
;另一组是星形联结的电阻性负载,每相电阻
,如图12-5所示。试求:(1)各组负载的相电流;(2)电路线电流;(3)三相有功功率。[西南大学2012研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image461.jpg?sign=1738881548-rFbuJ16fCSVaJdQLz78MSwBcPn1QapKl-0-6dca1e0d5ada328e7ed9cf742d581d51)
图12-5
解:设。
(1)对于星形负载,线电流等于相电流,为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image463.png?sign=1738881548-ESZnFgQx77G43khbgHnmgdGoPoOMIhSr-0-f4358ee04c211355f122e89c8a9edc29)
星形负载消耗有功为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image464.png?sign=1738881548-BYMK7Vtj1UqPXRFjshwzguRSmYSnoCdZ-0-5dcc015178e734a45b706286eedcb5d8)
对于三角形联结的负载,相电流为线电流的倍。将三角形联结等效为星形联结。得相电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image466.png?sign=1738881548-JPZE86gPX79hU0C49mOXRcRBuhrAaxcn-0-4d73a6e3b647695e1dabfe31e217eb19)
线电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image467.png?sign=1738881548-nJcbCS38qac8nYTkR2suECPqFHJxAT7r-0-ce8827f3cb466cbfe2144f301807dce0)
(2)电路线电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image468.png?sign=1738881548-WBov8klk2gBt9N6pioMbFwImqcWbf3xD-0-b0c573033d5d610004f5eeb5f951aa3d)
(3)三角形联结负载消耗有功为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image469.png?sign=1738881548-BnZoNqSpEblcqtnphKUTNKCYRoOCjZO6-0-08d390c138c2f5aa15395b9cf19a530f)
则总三相有功功率为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image470.png?sign=1738881548-IJYy3NGhG3sl9p2HdIxhbgeqGLjfJ4IC-0-11492cac279c363e615c8f07f9159e00)
2.图12-6(a)所示的对称三相电路中,三相电源线电压U1=300V,三相角接负载阻抗(容性)吸收功率P=4500W,三相电源供出的功率PS=7200W,线路阻抗Z1=(3+j3)Ω。试求线电流I1和负载阻抗Z。[天津大学2004研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image471.jpg?sign=1738881548-bDtSVBAYMyXllvpDoRDV9vlBd4CgWnKD-0-f6c4610e074a48877f4fa4fcda87adeb)
图12-6
解:由已知条件,线路阻抗消耗的平均功率为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image473.png?sign=1738881548-n6b2X8rkhtU7a7VGwMo8mjpZgEohpvTx-0-a136e25841f2caf4c9ff2a3b41d7b53f)
则三相电路的线电流为:
将△形负载等效成Y形负载,并取其一相得图(b)所示电路,其中:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image475.jpg?sign=1738881548-ApEA0za2t5eQcZYHbkZzpfv46CdSCttK-0-fc54568bbac324ce64ed0c0c10b7c264)
在图(b)中,相电流等于原电路的线电流。
再由负载消耗功率可知实部为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image477.jpg?sign=1738881548-IKadJRpe9ZBstn2e16pbW6wtc696DVdo-0-6399c95ce05c053a2c430d40bf143af9)
由题知,负载阻抗为容性,则有:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image478.jpg?sign=1738881548-3sFoR7seA3SdCBTWwPHcD74hz32Vygmy-0-ffe6d6c1c138b84f1eb0ce31c396da5d)
解得:XY=9Ω
则△形负载阻抗为:。
3.如图12-7所示对称三相电路中,对称三相电源频率为50Hz,线电压为380V,对称三相负载Z=(18+j24)Ω,对称三相电容负载C=58μF。试求:(1)各线电流;(2)电源发出的复功率。[北京交通大学2004研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image480.jpg?sign=1738881548-9FMl2kIcGzmxGajlBNNLGTCvdFC8zNHs-0-da555c092e655588ec9ce6c3513b1989)
图12-7
解:(1)已知电源线电压为380V,可知相电压(这里设定A相相电压相角为):
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image482.png?sign=1738881548-qfmqPtca20UrgmPoKAqiD2lptEx4hnVB-0-31b084214dbc3517fbb36ec3bcaaa3bd)
V
V
A
A
A
再由对称性可得、
:
A
A
(2)三相电源的复功率为
V·A
4.图12-8中A、B、C为对称三相电源,已知
图12-8
解:因为A、B、C为对称三相电源,所以
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image495.jpg?sign=1738881548-FGnKZuoftk7ys5F6xl7TMHT4kObdPxnA-0-ae332b1bb8c271b7700f54fdece5dda2)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image496.jpg?sign=1738881548-YDRtikhI6zAFWYtPSRtelbKkEyiHPIgG-0-1eed3abfaa93f243a7d99a6a74e67310)
先求阻抗Z的模值:
由题、
都闭合时,三个电流表读数均为5A,则有:
,解得
=132
。
(1)当开关S1闭合、S2断开时,A1、A2、A3的读数分别为:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image502.png?sign=1738881548-O9Z17xMOMw2z93i7ecczTcOH1DITkGkR-0-22ae0994768a0bbeb93b483735db8633)
由对称性知A
不变,即
A
(2)当开关S1断开、S2闭合时,A1、A2、A3的读数分别为:
A
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image507.png?sign=1738881548-yDEleNe7oeVkO9Xs01r7wCnVz0OaV0g3-0-a363981ca4aedea20c02cf9eac228d31)
A
5.如图12-9所示电路中,已知对称三相电压源线电压为380V,两组对称负载。第一组负载均为,第二组负载均为
,求:(1)电流表A1、A2、A3的示数;(2)当第二组A相负载发生短路故障后,电流表A1、A2、A3的示数;(3)当第二组A相负载发生断路故障后,电流表A1、A2、A3的示数。[北京交通大学2010研]
图12-9
解:(1)进行变换,得
。令
。
对于电流表A1:,故A1的示数为
A。
对于电流表A3:由,故A3的示数为11A。
对于电流表A2:,又
,
,
,所以
,故A2的示数为
A。
(2)对于电流表A3:,故A3的示数为
A。
对于电流表A2:,故A2的示数为26.9A。
对于电流表A1:设,则
,
,由此可得
,故
。
又,所以:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image533.png?sign=1738881548-WO5KC18kvqnuKGRskteINGAOQSjdKxLf-0-82b759cb7ea4663cc8d0d4214f3b2e9a)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image535.png?sign=1738881548-GboA0abMKD6NtPsSNiy4Eu3qDmXXDoxW-0-97ff5e2a38f996667bdabfe1238a9583)
因此,A1的示数为65.1A。
(3)对于电流表A1:,故A1的示数为46.5A。
对于电流表A2:,故A2的示数为26.9A。
对于电流表A3:,故A3的示数为9.5A。
6.图12-10所示三相对称电路,已知电压表的读数为,负载阻抗
,线路阻抗
,求图中电流表的读数和线电压UAB。[北京科技大学2011研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image542.jpg?sign=1738881548-EKfmyBtYnDP0r35gbpR6SiRZ95KagUnz-0-f5e5706ee5e81512de8c5e0caf2583af)
图12-10
解:(1)根据对称线电压和对称相电压之间的关系,可得对称相电压
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image543.png?sign=1738881548-NXXiefpnLlWKwjhRwojE2Cgm4s7VHLS7-0-2aa5bd16b4380a190c0384e3c5dee658)
则有
A
则电流表的示数为16.67A
(2)则
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image546.png?sign=1738881548-y9872JEAxSd7z3P8vGOqazTcDz5ZWi1z-0-03dcee4e470da3900f5f827e5b320fa8)
7.已知如图12-11所示电路中对称三相电源线电压V,阻抗Z1=50+j50Ω,Z2=20Ω,Z3=40+j80Ω,中线电阻R=3Ω。
(1)求图示功率表的读数;
(2)求A相电源uA发出的有功功率和无功功率。[清华大学2005研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image548.png?sign=1738881548-uRImnnemlBCPWmhrOJDS8phvxYbk69Ya-0-d319447eed3087e24a458d03c8cb9f74)
图12-11
解:(1)题图所示电路中,阻抗直接并接在A相电源上,对功率表的读数没有影响。求功率表读数电路如图12-12(a)所示,其单相计算电路如图12-12(b)所示。
图(a) 图(b)
图12-12
则可得:
V
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image552.png?sign=1738881548-xa3b5ekOOnBfyTUOXhX9ybDCI7RjUssu-0-c1ee42d2c028ab2657ac4156acce2aea)
功率表的读数为:。
(2)A相电源发出的有功功率:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image554.png?sign=1738881548-ieVTuWjyX1SPGzT2rHnHUvs4Uk7yOVwU-0-e16d21ec83ed448b5fb1260e7a033041)
8.如图12-13所示三相四线制电路中,接有两组对称三相负载和一个单相负载。已知对称三相电源相电压为220V,第一组对称三相负载、
、
的大小。[同济大学2009研]
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image562.png?sign=1738881548-9GwbkUZ298YNpDEl6Jf2TC8l3Rh7FR2q-0-786affe3eac5f06891cdf832c3e19ae8)
图12-13
解:设A相电压为,则第一组对称三相负载的电流
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image564.png?sign=1738881548-xXi5fn9bkaDgDH8sH3uQ6DHLYlggsyvf-0-4b28dbe9b7410e1a1dacfa4bb562e07c)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image565.png?sign=1738881548-p0q42Pz2ZD7cRCR0YlFmKd0M2rGsRFVl-0-8a6f580de7095081df012de5e0066192)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image566.png?sign=1738881548-lc5Uqaa0Nx3JvqQGlkeptChVBOznswMN-0-86fde8d14f4681d59ba360450c44e58d)
假设负载为星型连接,则:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image567.png?sign=1738881548-XlSS0H9zZ4znxXHxJCkWbaw4oHKbCUAt-0-c2780ba309d22cde41da02767cbd61d2)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image568.png?sign=1738881548-snz13IA1x6JICtLS31IBXRCBUQQ0u4q5-0-ed28c055641f67fad6e173d1723e1cfb)
故第二组对称三相负载的电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image569.png?sign=1738881548-ZStXzOppZnkkq4qnHQEAhdc7rDwCBYKA-0-7914f78cda621e4e3d54291c0678f30f)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image570.png?sign=1738881548-XlFfFjyBarSIyKVBadlfzq57FA65ESmG-0-b8646260fa6c8a942af0374ef53698b7)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image571.png?sign=1738881548-207AUfLTsiEN67OJ7VE5rGsp9Oxs7uH1-0-7f375be59938782c04997a1c2e678d5b)
单相负载的电流:。
电源端线电流:
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image574.png?sign=1738881548-N7P5hRsRVluIgGVWp12IrGtpQFvybXQl-0-7a5c329f09a7643e9e7bf97589b2a383)
![](https://epubservercos.yuewen.com/B7597F/15436365804435306/epubprivate/OEBPS/Images/image575.png?sign=1738881548-ZhwzObXdsROtgWnJpoFT3BPQUXGaSEEo-0-02a5975a21d305aabc2dadae74339a08)
因此:,
,
。